{"id":17799,"date":"2024-03-27T05:08:50","date_gmt":"2024-03-27T05:08:50","guid":{"rendered":"https:\/\/soicau5036.minhngocxoso.com\/?p=17799"},"modified":"2024-03-27T05:08:50","modified_gmt":"2024-03-27T05:08:50","slug":"chia-se-2-bai-toan-danh-lo-va-danh-dan-lo-hieu-qua-cao","status":"publish","type":"post","link":"https:\/\/soicaulo3mien.com\/chia-se-2-bai-toan-danh-lo-va-danh-dan-lo-hieu-qua-cao\/","title":{"rendered":"chia s\u1ebb 2 b\u00e0i to\u00e1n \u0111\u00e1nh l\u00f4 v\u00e0 \u0111\u00e1nh d\u00e0n l\u00f4 hi\u1ec7u qu\u1ea3 cao"},"content":{"rendered":"
<\/p>\n\n\n
Xin ch\u00e0o c\u00e1c b\u1ea1n, h\u00f4m nay ch\u00fang t\u00f4i s\u1ebd chia s\u1ebb cho c\u00e1c b\u1ea1n v\u1ec1 c\u00e1c ph\u00e9p to\u00e1n trong l\u00f4 \u0111\u1ec1 c\u1ef1c k\u00ec hay v\u00e0 ch\u00ednh x\u00e1c nh\u00e9. D\u01b0\u1edbi \u0111\u00e2y l\u00e0 2 b\u00e0i to\u00e1n \u0111\u00e1nh l\u00f4 v\u00e0 \u0111\u00e1nh d\u00e0n l\u00f4, c\u00e1c b\u1ea1n c\u00f3 th\u1ec3 v\u1eadn d\u1ee5ng ch\u01a1i d\u00e0n l\u00f4 4 con, d\u00e0n l\u00f4 8 con \u0111\u1ec1u \u0111\u01b0\u1ee3c nh\u00e9, c\u00f9ng theo d\u00f5i nh\u00e9:<\/p>\n\n\n\n
Lu\u1eadt ch\u01a1i l\u00f4 \u0111\u1ea1i lo\u1ea1i nh\u01b0 sau: S\u00e1ng, b\u1ea1n \u0111\u1eb7t c\u01b0\u1ee3c 1 con s\u1ed1 trong ph\u1ea1m vi t\u1eeb 00 \u0111\u1ebfn 99 v\u00e0 m\u1ed9t s\u1ed1 \u0111i\u1ec3m l\u00f4, a \u0111i\u1ec3m ch\u1eb3ng h\u1ea1n. M\u1ed7i \u0111i\u1ec3m l\u00f4 ph\u1ea3i chi ph\u00ed 23000 (\u0111\u1ed3ng). D\u00e0n l\u00f4 g\u1ed3m 27 con l\u00f4 (l\u00e0 2 ch\u1eef s\u1ed1 cu\u1ed1i c\u1ee7a c\u00e1c s\u1ed1 t\u1ea1i c\u00e1c gi\u1ea3i X\u1ed5 s\u1ed1 c\u1ee7a Nh\u00e0 n\u01b0\u1edbc ph\u00e1t h\u00e0nh).<\/p>\n\n\n\n
N\u1ebfu c\u00f3 k con l\u00f4 tr\u00f9ng v\u1edbi s\u1ed1 b\u1ea1n \u0111\u00e3 \u0111\u1eb7t c\u01b0\u1ee3c th\u00ec s\u1ed1 ng\u01b0\u1eddi ta g\u1ecdi l\u00e0 b\u1ea1n \u0111\u00e3 tr\u00fang \u201ck nh\u00e1y\u201d. M\u1ed7i \u201cnh\u00e1y\u201d, ch\u1ee7 l\u00f4 tr\u1ea3 cho b\u1ea1n 80000.a (\u0111\u1ed3ng).<\/p>\n\n\n\n
Gi\u1ea3 s\u1eed anh b\u1ea1n c\u1ee7a ch\u00fang ta \u0111\u00e1nh 1 \u0111i\u1ec3m l\u00f4. Anh ta chi h\u1ebft 23000. D\u1ec5 th\u1ea5y \u0111\u00e1nh l\u00f4 l\u00e0 m\u1ed9t ph\u00e9p th\u1eed Bernoulli.<\/p>\n\n\n\n
X\u00e1c su\u1ea5t \u0111\u1ec3 anh ta tr\u00fang \u0111\u00fang k nh\u00e1y (k=0,1,\u2026,27) l\u00e0 Ck27(0,01)k(0,99)27\u2212k<\/p>\n\n\n\n
N\u1ebfu tr\u00fang, anh ta \u0111\u01b0\u1ee3c 80000.k (\u0111\u1ed3ng). Nh\u01b0 v\u1eady l\u00e3i :<\/p>\n\n\n\n
80000.k\u201323000 (\u0111\u1ed3ng)<\/p>\n\n\n\n
E=\u2211k=027[Ck27.(0,01)k(0,99)27\u2212k.(80k\u221223)]<\/p>\n\n\n\n
=80\u2211k=127[kCk27.(0,01)k(0,99)27\u2212k.]\u221223<\/p>\n\n\n\n
=80.27100\u2211k=026[Ck26.(0,01)k(0,99)26\u2212k.]\u221223<\/p>\n\n\n\n
=8.2,7\u201323=\u22121,4 (ngh\u00ecn \u0111\u1ed3ng)<\/p>\n\n\n\n
V\u1eady trung b\u00ecnh anh ta l\u1ed7 1400 (\u0111\u1ed3ng).<\/p>\n\n\n\n
R\u00f5 r\u00e0ng l\u00e0 \u0111\u00e1nh l\u00f4 l\u1ed7 \u00edt h\u01a1n \u0111\u00e1nh \u0111\u1ec1<\/p>\n\n\n\n